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Return dir = AXIS.x ? Math.acos(s(rad)) : Math.asin(-Math.sin(rad)) I would never use degrees, that is only ever needed for display only. % 360) I am doing it wrong and there is a better way. I have a general rule of thumb that if I ever find my self having to normalize a cyclic value E.G. Messing around with the cyclic angle is not needed. a vector has two scalars x,y if you reflect along X you negate x, if you reflex along Y you negate y. You can calculate the distance ‘dis’ by multiplying the separation distance by the beam angle tangent. Let ‘dis’ equal the horizontal distance covered by the light between reflections off either mirror. The problem is just one of negating the scalar associated with the direction of reflection. Nowadays, things have been easier for learners, thanks to reflection calculators in place.
#Angle of reflection calculator code#
The code is just too complex for something so simple. Learn to work in radians, it makes a lot of angle related maths so much easier. Why are you using degrees, NO Math functions uses degrees, the only time you need to use degrees is for output, which generally is never needed. It would pay to check both (upper and lower) or convert to lowercase, or best use a defined constant, Also you use a string and to humans "x", "X" and "y", "Y" have the same meaning, but your code sees them differently, this is never a good thing. Axis? is it the axis of reflection or the axis to reflex from. No need to find each number in the code base. Then if you want to change to radians const A90 = Math.PI / 2 If you find your self adding the same numbers over and over it is a good sign that a defined constant is better. an expression, you don't need to use both function reflectAngle(angle, axis) denote the end of To calculate Deflection Angle when Length of Curve is Given, you need Length of curve (L) & Radius of curve (R). The current implementation came about through iterative refactoring of a much more verbose and redundant version, however I can't vocalise exactly why some parts are necessary, but they appear to satisfy the requirements and I'm confident it works based on a number of tests. A central angle is an angle whose vertex is the center of a circle and whose legs (sides) are radii intersecting the circle in two distinct points is calculated using Central Angle Length of curve / Radius of curve (pi /180). Given those two factors, the actual boundary is implied, since a projectile travelling at an angle of 315° (where 0°/360° sit at 3 o'clock) and colliding with a horizontal boundary (the x axis) must be colliding with the top boundary.
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I've developed a function to calculate the exit angle of a projectile after it collides with a boundary/edge inside a rectangular space, based on the entry angle and the axis it is colliding with.